What is the solution for f^'(x)=sqrt(x+1) ?

The solution for f^'(x)=sqrt(x+1) is f(x)= 2/3 (x+1)^{3/2}+c_{1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f^'(x)=sqrt(x+1)

f^{^{'}} (x) = x + 1

f (x) = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

Solution steps

f^{'} (x) = x + 1

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int x + 1 d x

\int x + 1 d x = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

f (x) = \frac{2}{3} (x + 1)^{\frac{3}{2}} + c_{1}

\frac{d}{d x} (- sin (2 x) \cdot 2 + cos (2 x) \cdot 2)

\int x^{2} - 7 x + 8 d x

- 3 x^{2} + 6 x + 4

n = 1 \sum \infty n^{5} (1 + n^{6})^{1}

What is the solution for f^'(x)=sqrt(x+1) ?
The solution for f^'(x)=sqrt(x+1) is f(x)= 2/3 (x+1)^{3/2}+c_{1}