What is the solution for y^'=cos^2(x)cos^2(2y) ?

The solution for y^'=cos^2(x)cos^2(2y) is y=(arctan(x+1/2 sin(2x)+c_{1}))/2+(pin)/2

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y^'=cos^2(x)cos^2(2y)

y^{^{'}} = cos^{2} (x) cos^{2} (2 y)

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

Solution steps

y^{'} (x) = cos^{2} (x) cos^{2} (2 y)

Solve separable ODE:

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

y = \frac{arctan ( x + \frac{1}{2} sin ( 2 x ) + c _{1} )}{2} + \frac{πn}{2}

\int \frac{x}{x ^{4} + 49} d x

x \to 2 - lim (\frac{5 x}{x - 2})

(x + i y)^{2}

y^{^{'}} + (\frac{2}{x}) y = 0

\int (\frac{1 - x}{x})^{2} d x

What is the solution for y^'=cos^2(x)cos^2(2y) ?
The solution for y^'=cos^2(x)cos^2(2y) is y=(arctan(x+1/2 sin(2x)+c_{1}))/2+(pin)/2