What is the tangent of f(x)=x^3+9x^2+34x+15,\at x=7 ?

The tangent of f(x)=x^3+9x^2+34x+15,\at x=7 is y=307x-1112

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tangent of f(x)=x^3+9x^2+34x+15,\at x=7

tangent of

f (x) = x^{3} + 9 x^{2} + 34 x + 15, at x = 7

y = 307 x - 1112

Solution steps

Find the tangent point:

(7, 1037)

Find the slope of

f (x) = x^{3} + 9 x^{2} + 34 x + 15 : \frac{df ( x )}{d x} = 3 x^{2} + 18 x + 34

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 307

Find the line with slope m=

307

and passing through

(7, 1037) : y = 307 x - 1112

y = 307 x - 1112

cos (x^{2})

\frac{d}{d x} (e^{- x^{2}} + x)

g (x) = 3 x, at x = 4

y

\frac{d}{d x} (\frac{( - 3 x ^{2} )}{( ( x ^{2} - 2 x + 1 ) )})

What is the tangent of f(x)=x^3+9x^2+34x+15,\at x=7 ?
The tangent of f(x)=x^3+9x^2+34x+15,\at x=7 is y=307x-1112