What is the derivative of e^{-x^2}+x ?

The derivative of e^{-x^2}+x is -2e^{-x^2}x+1

What is the first derivative of e^{-x^2}+x ?

The first derivative of e^{-x^2}+x is -2e^{-x^2}x+1

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\frac{d}{d x} (e^{- x^{2}} + x)

- 2 e^{- x^{2}} x + 1

Solution steps

\frac{d}{d x} (e^{- x^{2}} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- x^{2}}) + \frac{d x}{d x}

\frac{d}{d x} (e^{- x^{2}}) = - 2 e^{- x^{2}} x

\frac{d x}{d x} = 1

= - 2 e^{- x^{2}} x + 1

g (x) = 3 x, at x = 4

y

\frac{d}{d x} (\frac{( - 3 x ^{2} )}{( ( x ^{2} - 2 x + 1 ) )})

\int_{1}^{\infty} \frac{x}{9 + x ^{2}} d x

\int 1 + tan^{2} (x) d x

What is the derivative of e^{-x^2}+x ?
The derivative of e^{-x^2}+x is -2e^{-x^2}x+1
What is the first derivative of e^{-x^2}+x ?
The first derivative of e^{-x^2}+x is -2e^{-x^2}x+1