What is the integral from 0 to sqrt(x of)2t ?

The integral from 0 to sqrt(x of)2t is x

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integral from 0 to sqrt(x of)2t

\int_{0}^{x} 2 t d t

x

Solution steps

\int_{0}^{x} 2 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{x} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{x}

= 2 [\frac{t ^{2}}{2}]_{0}^{x}

Compute the boundaries:

\frac{x}{2}

= 2 \cdot \frac{x}{2}

Simplify

= x

\frac{d}{d x} (- \frac{3}{16 x ^{\frac{7}{4}}})

ln (9 - 2 x)

\frac{d}{d x} (\frac{1}{3 x + 5})

\int_{1}^{2} x d x

\frac{d}{d x} ([x + (x + sin^{2} (x))^{7}]^{4})

What is the integral from 0 to sqrt(x of)2t ?
The integral from 0 to sqrt(x of)2t is x