What is area x^2-4,x=-4,x=3,y=0 ?

The answer to area x^2-4,x=-4,x=3,y=0 is 71/3

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area x^2-4,x=-4,x=3,y=0

area

x^{2} - 4, x = - 4, x = 3, y = 0

\frac{71}{3}

Decimal

23.66666 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{3} x^{2} - 4 d x

Solve

\int_{- 4}^{3} x^{2} - 4 d x : \frac{71}{3}

The area is:

= \frac{71}{3}

\int_{0}^{1} (3 x^{2} - 4 x + 1) d x

y^{^{''}} + \frac{1}{4} y = 0

x \to - 4 lim (3)

x \to \infty lim (\frac{1}{lo g _{2} ( x )})

\int_{- 1}^{0} \frac{1}{x ^{2}} d x