What is (\partial)/(\partial t)(xzt^2sqrt(y+1)) ?

The answer to (\partial)/(\partial t)(xzt^2sqrt(y+1)) is 2xztsqrt(y+1)

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(\partial)/(\partial t)(xzt^2sqrt(y+1))

\frac{\partial}{\partial t} (x z t^{2} y + 1)

2 x z t y + 1

Solution steps

\frac{\partial}{\partial t} (x z t^{2} y + 1)

Treat

x, z, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x z y + 1 \frac{\partial}{\partial t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x z y + 1 \cdot 2 t^{2 - 1}

Simplify

= 2 x z t y + 1

\int e^{x} 1 + e^{x} d x

\frac{A}{y ^{10}} + B e^{y}

y = x + 1, y = x^{2} - 1

\int \frac{x ^{2} - x + 30}{x ^{3} + 5 x} d x

\frac{\partial}{\partial x} (cos (w + x) sin (y - z))

What is (\partial)/(\partial t)(xzt^2sqrt(y+1)) ?
The answer to (\partial)/(\partial t)(xzt^2sqrt(y+1)) is 2xztsqrt(y+1)