What is the solution for 3y^{''}-10y^'+3y=0,y(0)=-5,y^'(0)=-1 ?

The solution for 3y^{''}-10y^'+3y=0,y(0)=-5,y^'(0)=-1 is y=(-5+21/4)e^{3t}-21/4 e^{t/3}

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3y^{''}-10y^'+3y=0,y(0)=-5,y^'(0)=-1

3 y^{^{''}} - 10 y^{^{'}} + 3 y = 0, y (0) = - 5, y^{^{'}} (0) = - 1

y = (- 5 + \frac{21}{4}) e^{3 t} - \frac{21}{4} e^{\frac{t}{3}}

Solution steps

3 y^{''} (t) - 10 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = (- 5 + \frac{21}{4}) e^{3 t} - \frac{21}{4} e^{\frac{t}{3}}

y = (- 5 + \frac{21}{4}) e^{3 t} - \frac{21}{4} e^{\frac{t}{3}}

\int_{0}^{π} sin^{2} (x) cos (x) d x

f (x) = (6 x - 5)^{\frac{1}{2}}, at x = 1

\frac{d y}{d x} = 8 x^{- 9}

\frac{d}{d x} (\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}})

y = sin (tan (5 x))

What is the solution for 3y^{''}-10y^'+3y=0,y(0)=-5,y^'(0)=-1 ?
The solution for 3y^{''}-10y^'+3y=0,y(0)=-5,y^'(0)=-1 is y=(-5+21/4)e^{3t}-21/4 e^{t/3}