What is the derivative of xln(x+2x) ?

The derivative of xln(x+2x) is ln(x)+3

What is the first derivative of xln(x+2x) ?

The first derivative of xln(x+2x) is ln(x)+3

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\frac{d}{d x} (x ln (x) + 2 x)

ln (x) + 3

Solution steps

\frac{d}{d x} (x ln (x) + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x ln (x)) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x ln (x)) = ln (x) + 1

\frac{d}{d x} (2 x) = 2

= ln (x) + 1 + 2

Simplify

= ln (x) + 3

\frac{\partial}{\partial x} (x^{2} ln (x^{2} + y^{2}))

\int (7 x^{6} + 7 x^{3} + 4) d x

\int e^{l n (x^{2})} x d x

\frac{d}{d x} (e^{2 x} - cos (2 x))

x \to 0 lim (\frac{( sin ( 4 x ) )}{x})

What is the derivative of xln(x+2x) ?
The derivative of xln(x+2x) is ln(x)+3
What is the first derivative of xln(x+2x) ?
The first derivative of xln(x+2x) is ln(x)+3