What is the derivative of sqrt(-3x+7) ?

The derivative of sqrt(-3x+7) is -3/(2sqrt(-3x+7))

What is the first derivative of sqrt(-3x+7) ?

The first derivative of sqrt(-3x+7) is -3/(2sqrt(-3x+7))

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\frac{d}{d x} (- 3 x + 7)

- \frac{3}{2 - 3 x + 7}

Solution steps

\frac{d}{d x} (- 3 x + 7)

Apply the chain rule:

\frac{1}{2 - 3 x + 7} \frac{d}{d x} (- 3 x + 7)

= \frac{1}{2 - 3 x + 7} \frac{d}{d x} (- 3 x + 7)

\frac{d}{d x} (- 3 x + 7) = - 3

= \frac{1}{2 - 3 x + 7} (- 3)

Simplify

\frac{1}{2 - 3 x + 7} (- 3) : - \frac{3}{2 - 3 x + 7}

= - \frac{3}{2 - 3 x + 7}

\frac{\partial}{\partial x} (3 e^{x y + 4})

\frac{d y}{d x} = x y + 5 x + 2 y + 10

13 sin (2 t)

\int (\frac{10}{1 - sin ^{2} ( x )}) d x

n = 1 \sum \infty \frac{( ( - 1 ) ^{(n - 1)} )}{( n ^{3} )}

What is the derivative of sqrt(-3x+7) ?
The derivative of sqrt(-3x+7) is -3/(2sqrt(-3x+7))
What is the first derivative of sqrt(-3x+7) ?
The first derivative of sqrt(-3x+7) is -3/(2sqrt(-3x+7))