What is (\partial)/(\partial x)(tan^2(x+y)) ?

The answer to (\partial)/(\partial x)(tan^2(x+y)) is 2tan(x+y)sec^2(x+y)

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(\partial)/(\partial x)(tan^2(x+y))

\frac{\partial}{\partial x} (tan^{2} (x + y))

2 tan (x + y) sec^{2} (x + y)

Solution steps

\frac{\partial}{\partial x} (tan^{2} (x + y))

Treat

y

as a constant

Apply the chain rule:

2 tan (x + y) \frac{\partial}{\partial x} (tan (x + y))

= 2 tan (x + y) \frac{\partial}{\partial x} (tan (x + y))

\frac{\partial}{\partial x} (tan (x + y)) = sec^{2} (x + y)

= 2 tan (x + y) sec^{2} (x + y)

\int - 9.8 t d t

n = 0 \sum \infty (\frac{5}{2})^{n}

n = 1 \sum \infty \frac{1}{3 ^{n} + 5}

\frac{\partial}{\partial x} (2 x + 4 y)

n = 1 \sum \infty \frac{6}{π \cdot n}

What is (\partial)/(\partial x)(tan^2(x+y)) ?
The answer to (\partial)/(\partial x)(tan^2(x+y)) is 2tan(x+y)sec^2(x+y)