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Popular >

derivative of y=ln(sqrt(x^2+4))

Solution

derivative of

y = ln (x^{2} + 4)

Solution

\frac{x}{x ^{2} + 4}

Solution steps

\frac{d}{d x} (ln (x^{2} + 4))

Apply the chain rule:

\frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

= \frac{1}{x ^{2} + 4} \frac{d}{d x} (x^{2} + 4)

\frac{d}{d x} (x^{2} + 4) = \frac{x}{x ^{2} + 4}

= \frac{1}{x ^{2} + 4} \cdot \frac{x}{x ^{2} + 4}

Simplify

\frac{1}{x ^{2} + 4} \cdot \frac{x}{x ^{2} + 4} : \frac{x}{x ^{2} + 4}

= \frac{x}{x ^{2} + 4}

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Frequently Asked Questions (FAQ)

What is the derivative of y=ln(sqrt(x^2+4)) ?
The derivative of y=ln(sqrt(x^2+4)) is x/(x^2+4)
What is the first derivative of y=ln(sqrt(x^2+4)) ?
The first derivative of y=ln(sqrt(x^2+4)) is x/(x^2+4)