What is the first derivative of 8xy ?

The first derivative of 8xy is 8y

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derivative of 8xy

derivative of

8 x y

8 y

Solution steps

\frac{d}{d x} (8 x y)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 y \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= 8 y \cdot 1

Simplify

= 8 y

(2 x + \frac{2}{y}) + (\frac{2 x ^{2}}{y} + \frac{2 x}{y ^{2}}) y^{^{'}} = 0

\frac{d}{d x} (x (x + 1))

\int_{0}^{4} f (x) d x

(x - 2) y^{^{'}} + y = 3 x^{2} + 2 x

n = 0 \sum \infty \frac{1}{( 2 n + 1 ) ^{4}}