What is the derivative of f(x)=arccos(x^2) ?

The derivative of f(x)=arccos(x^2) is -(2x)/(sqrt(1-x^4))

What is the first derivative of f(x)=arccos(x^2) ?

The first derivative of f(x)=arccos(x^2) is -(2x)/(sqrt(1-x^4))

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derivative of

f (x) = arccos (x^{2})

- \frac{2 x}{1 - x ^{4}}

Solution steps

\frac{d}{d x} (arccos (x^{2}))

Apply the chain rule:

- \frac{1}{1 - ( x ^{2} ) ^{2}} \frac{d}{d x} (x^{2})

= - \frac{1}{1 - ( x ^{2} ) ^{2}} \frac{d}{d x} (x^{2})

\frac{d}{d x} (x^{2}) = 2 x

= - \frac{1}{1 - ( x ^{2} ) ^{2}} \cdot 2 x

Simplify

- \frac{1}{1 - ( x ^{2} ) ^{2}} \cdot 2 x : - \frac{2 x}{1 - x ^{4}}

= - \frac{2 x}{1 - x ^{4}}

\int x^{18} e^{x^{19}} d x

y^{^{''}} + y = 4 x + 10

x y^{^{'}} = y + x^{2} - y^{2}

x \to 1 - lim (\frac{5}{x ^{3} - 1})

f (x) = 4 x^{2} - 2 x + 1, at x = 3

What is the derivative of f(x)=arccos(x^2) ?
The derivative of f(x)=arccos(x^2) is -(2x)/(sqrt(1-x^4))
What is the first derivative of f(x)=arccos(x^2) ?
The first derivative of f(x)=arccos(x^2) is -(2x)/(sqrt(1-x^4))