What is the integral from pi/2 to pi of pisin^2(x) ?

The integral from pi/2 to pi of pisin^2(x) is (pi^2)/4

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integral from pi/2 to pi of pisin^2(x)

\int_{\frac{π}{2}}^{π} π sin^{2} (x) d x

\frac{π ^{2}}{4}

Decimal Notation

2.46740 \dots

Solution steps

\int_{\frac{π}{2}}^{π} π sin^{2} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{\frac{π}{2}}^{π} sin^{2} (x) d x

Rewrite using trig identities

= π \cdot \int_{\frac{π}{2}}^{π} \frac{1 - cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \frac{1}{2} \cdot \int_{\frac{π}{2}}^{π} 1 - cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π \frac{1}{2} (\int_{\frac{π}{2}}^{π} 1 d x - \int_{\frac{π}{2}}^{π} cos (2 x) d x)

\int_{\frac{π}{2}}^{π} 1 d x = π - \frac{π}{2}

\int_{\frac{π}{2}}^{π} cos (2 x) d x = 0

= π \frac{1}{2} (π - \frac{π}{2} - 0)

Simplify

π \frac{1}{2} (π - \frac{π}{2} - 0) : \frac{π ^{2}}{4}

= \frac{π ^{2}}{4}

f (x) = 4 x^{2} + 2 x + 5, at x = 3

t (\frac{d y}{d t}) + 33 y = \frac{1}{t}

\frac{d}{d x} (- 4 x^{2} + x + 5)

x \to π - lim (ln (sin (x)))

f (x) = 9 x e^{x}

What is the integral from pi/2 to pi of pisin^2(x) ?
The integral from pi/2 to pi of pisin^2(x) is (pi^2)/4