What is the integral of (4+cos(x))/(x^2) ?

The integral of (4+cos(x))/(x^2) is -(4+cos(x))/x-\Si(x)+C

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integral of (4+cos(x))/(x^2)

\int \frac{4 + cos ( x )}{x ^{2}} d x

- \frac{4 + cos ( x )}{x} - Si (x) + C

Solution steps

\int \frac{4 + cos ( x )}{x ^{2}} d x

Apply Integration By Parts

: - \frac{4 + cos ( x )}{x} - \int \frac{sin ( x )}{x} d x

= - \frac{4 + cos ( x )}{x} - \int \frac{sin ( x )}{x} d x

\int \frac{sin ( x )}{x} d x = Si (x)

= - \frac{4 + cos ( x )}{x} - Si (x)

Add a constant to the solution

= - \frac{4 + cos ( x )}{x} - Si (x) + C

\int \frac{2}{x ^{2} + 1} - x^{2} d x

f (2) = - x^{2} + 6 x - 3

\frac{x}{1 + x ^{2}}, \frac{x ^{2}}{1 + x ^{3}}

\frac{d}{d x} (\frac{1}{4} sin (4 x))

n = 1 \sum \infty (\frac{2}{3})^{n - 1}

What is the integral of (4+cos(x))/(x^2) ?
The integral of (4+cos(x))/(x^2) is -(4+cos(x))/x-\Si(x)+C