What is the derivative of y=(sqrt(x))/(5+x) ?

The derivative of y=(sqrt(x))/(5+x) is (5-x)/(2sqrt(x)(5+x)^2)

What is the first derivative of y=(sqrt(x))/(5+x) ?

The first derivative of y=(sqrt(x))/(5+x) is (5-x)/(2sqrt(x)(5+x)^2)

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derivative of

y = \frac{x}{5 + x}

\frac{5 - x}{2 x ( 5 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{5 + x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ) ( 5 + x ) - \frac{d}{d x} ( 5 + x ) x}{( 5 + x ) ^{2}}

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (5 + x) = 1

= \frac{\frac{1}{2 x} ( 5 + x ) - 1 \cdot x}{( 5 + x ) ^{2}}

Simplify

\frac{\frac{1}{2 x} ( 5 + x ) - 1 \cdot x}{( 5 + x ) ^{2}} : \frac{5 - x}{2 x ( 5 + x ) ^{2}}

= \frac{5 - x}{2 x ( 5 + x ) ^{2}}

\int_{- 1}^{1} 7^{x} d x

x \to - 1 lim (\frac{x}{x + 1})

\frac{d}{d x} ((ln (3))^{x})

x^{4} - 5 x^{2} + 4, at x = 1

\frac{d y}{d t} = 2 y - y^{2}

What is the derivative of y=(sqrt(x))/(5+x) ?
The derivative of y=(sqrt(x))/(5+x) is (5-x)/(2sqrt(x)(5+x)^2)
What is the first derivative of y=(sqrt(x))/(5+x) ?
The first derivative of y=(sqrt(x))/(5+x) is (5-x)/(2sqrt(x)(5+x)^2)