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Popular >

integral of 4^{-2x}

Solution

\int 4^{- 2 x} d x

Solution

16 x + C

Solution steps

\int 4^{- 2 x} d x

Apply u-substitution

: \int - 8 d u

= \int - 8 d u

Integral of a constant:

\int a d x = a x

= (- 8) u

Substitute back

u = - 2 x

= (- 8) (- 2 x)

Simplify

= 16 x

Add a constant to the solution

= 16 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 4^{-2x} ?
The integral of 4^{-2x} is 16x+C