What is the solution for (dy}{dx}=\frac{(x+1))/y ?

The solution for (dy}{dx}=\frac{(x+1))/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}

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(dy}{dx}=\frac{(x+1))/y

\frac{d y}{d x} = \frac{( x + 1 )}{y}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( x + 1 )}{y}

Solve separable ODE:

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

y = x^{2} + 2 x + c_{1}, y = - x^{2} + 2 x + c_{1}

\frac{\partial}{\partial y} (x y e^{- 5 y})

\frac{d}{d x} (\frac{16}{x ^{3}})

5 y^{^{'}} + y = - 3

f (x) = 3 x^{4} - 8 x^{3} + 2

\frac{d}{d x} (5 e^{- 2 x} sin (3 x))

What is the solution for (dy}{dx}=\frac{(x+1))/y ?
The solution for (dy}{dx}=\frac{(x+1))/y is y=sqrt(x^2+2x+c_{1)},y=-sqrt(x^2+2x+c_{1)}