What is the limit as n approaches 0 of sin(1/n) ?

The limit as n approaches 0 of sin(1/n) is diverges

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limit as n approaches 0 of sin(1/n)

n \to 0 lim (sin (\frac{1}{n}))

diverges

Solution steps

n \to 0 lim (sin (\frac{1}{n}))

Apply Limit Divergence Criterion:

diverges

= diverges

\frac{d}{d x} (4 x^{2} cos (x) - x)

\frac{d ^{2}}{d x ^{2}} (x^{2} + y^{2})

f (x) = 7 x + 4

f (x) = - 2 sin (x), at x = - π

\int_{0}^{10} x^{2} - 6 x + 5 d x

What is the limit as n approaches 0 of sin(1/n) ?
The limit as n approaches 0 of sin(1/n) is diverges