What is the integral of 2y^2+ye^{xy} ?

The integral of 2y^2+ye^{xy} is 2y^2x+e^{yx}+C

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integral of 2y^2+ye^{xy}

\int 2 y^{2} + y e^{x y} d x

2 y^{2} x + e^{y x} + C

Solution steps

\int 2 y^{2} + y e^{x y} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 y^{2} d x + \int y e^{y x} d x

\int 2 y^{2} d x = 2 y^{2} x

\int y e^{y x} d x = e^{y x}

= 2 y^{2} x + e^{y x}

Add a constant to the solution

= 2 y^{2} x + e^{y x} + C

(5 y^{2} - x y) d x + (x^{2}) d y = 0

y^{^{''}} - 3 y^{^{'}} = 8

\frac{\partial}{\partial x} (y^{2} e^{x yz})

x \to 1 - lim ((x - 2)^{2})

\frac{\partial}{\partial x} (3 x^{2} + 3 y^{2} - 15)

What is the integral of 2y^2+ye^{xy} ?
The integral of 2y^2+ye^{xy} is 2y^2x+e^{yx}+C