What is the integral of x/(e^{x^2)} ?

The integral of x/(e^{x^2)} is -1/2 e^{-x^2}+C

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integral of x/(e^{x^2)}

\int \frac{x}{e ^{x^{2}}} d x

- \frac{1}{2} e^{- x^{2}} + C

Solution steps

\int \frac{x}{e ^{x^{2}}} d x

Apply exponent rule:

\frac{1}{a ^{b}} = a^{- b}

\frac{x}{e ^{x^{2}}} = (x) e^{- x^{2}}

= \int x e^{- x^{2}} d x

Apply u-substitution

: \int - \frac{e ^{u}}{2} d u

= \int - \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - \frac{1}{2} e^{u}

Substitute back

u = - x^{2}

= - \frac{1}{2} e^{- x^{2}}

Add a constant to the solution

= - \frac{1}{2} e^{- x^{2}} + C

\int \frac{1 + x ^{2}}{1 + x ^{4}} d x

\frac{\partial}{\partial y} (- x^{2} y)

f (x) = \frac{1}{x - 1}, at x = - 4

y^{^{'}} = (t y^{2} - 1) y

- 2 x^{2}, at 1

What is the integral of x/(e^{x^2)} ?
The integral of x/(e^{x^2)} is -1/2 e^{-x^2}+C