What is (\partial)/(\partial y)(-x^2y) ?

The answer to (\partial)/(\partial y)(-x^2y) is -x^2

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(\partial)/(\partial y)(-x^2y)

\frac{\partial}{\partial y} (- x^{2} y)

- x^{2}

Solution steps

\frac{\partial}{\partial y} (- x^{2} y)

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - x^{2} \cdot 1

Simplify

= - x^{2}

f (x) = \frac{1}{x - 1}, at x = - 4

y^{^{'}} = (t y^{2} - 1) y

- 2 x^{2}, at 1

\frac{d}{d x} (e^{x^{3} + 5 x})

\int \frac{( sin ^{2} ( x ) )}{cos ( x )} d x

What is (\partial)/(\partial y)(-x^2y) ?
The answer to (\partial)/(\partial y)(-x^2y) is -x^2