What is the integral of \sqrt[3]{x^{-2}} ?

The integral of \sqrt[3]{x^{-2}} is 3\sqrt[3]{x}+C

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integral of \sqrt[3]{x^{-2}}

Solution steps

x^{- 2} = \frac{1}{x ^{2}}

Simplify

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Simplify

assuming

x \geq 0

= 1 \cdot \int \frac{1}{x ^{\frac{2}{3}}} d x

Apply the Power Rule

: 3 x^{\frac{1}{3}}

= 1 \cdot 3 x^{\frac{1}{3}}

Simplify

Add a constant to the solution

\int \frac{1}{sin ^{3} ( x )} d x

f (x) = 38 - x^{2}, (- 6, 2)

\int \frac{19}{r ^{2} + 1} d r

\int - 36 sin (6 x) d x

n = 1 \sum \infty \frac{n !}{2 0 ^{n}}

What is the integral of \sqrt[3]{x^{-2}} ?
The integral of \sqrt[3]{x^{-2}} is 3\sqrt[3]{x}+C