What is the integral of (19)/(r^2+1) ?

The integral of (19)/(r^2+1) is 19arctan(r)+C

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integral of (19)/(r^2+1)

\int \frac{19}{r ^{2} + 1} d r

19 arctan (r) + C

Solution steps

\int \frac{19}{r ^{2} + 1} d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 19 \cdot \int \frac{1}{r ^{2} + 1} d r

Use the common integral:

\int \frac{1}{r ^{2} + 1} d r = arctan (r)

= 19 arctan (r)

Add a constant to the solution

= 19 arctan (r) + C

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What is the integral of (19)/(r^2+1) ?
The integral of (19)/(r^2+1) is 19arctan(r)+C