What is (\partial)/(\partial y)(-ycos(x)) ?

The answer to (\partial)/(\partial y)(-ycos(x)) is -cos(x)

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(\partial)/(\partial y)(-ycos(x))

\frac{\partial}{\partial y} (- y cos (x))

- cos (x)

Solution steps

\frac{\partial}{\partial y} (- y cos (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - cos (x) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - cos (x) \cdot 1

Simplify

= - cos (x)

\frac{s + 1}{( s + 1 ) ( s ^{2} + 2 )}

y = - x^{2} + 2 x + 2, y = x - 4

\int \frac{d ^{2} y}{1} d x^{2}

\int (sin^{2} (x) + cos^{2} (x) - 1) d x

\int - \frac{6 x}{5} d x

What is (\partial)/(\partial y)(-ycos(x)) ?
The answer to (\partial)/(\partial y)(-ycos(x)) is -cos(x)