What is the sum from n=0 to infinity of 2+e^{-3n} ?

The sum from n=0 to infinity of 2+e^{-3n} is diverges

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sum from n=0 to infinity of 2+e^{-3n}

n = 0 \sum \infty 2 + e^{- 3 n}

diverges

Solution steps

n = 0 \sum \infty 2 + e^{- 3 n}

Apply Series Divergence Test:

diverges

= diverges

g (s) = \frac{5}{s - 3}

\frac{d}{d x} (- 2 x cos (x))

\frac{5}{2} y^{4} y^{^{'}} = \frac{y ^{5} + 4}{x ^{3}}

(2 x + y) d x + (x + 3 y) d y = 0

y = 4 x^{2} - x^{3}, (1, 3)

What is the sum from n=0 to infinity of 2+e^{-3n} ?
The sum from n=0 to infinity of 2+e^{-3n} is diverges