What is the tangent of f(x)=x^2+3x+4pi ?

The tangent of f(x)=x^2+3x+4pi is y=(2a_{0}+3)x-a_{0}^2+4pi

Popular >

tangent of f(x)=x^2+3x+4pi

tangent of

f (x) = x^{2} + 3 x + 4 π

y = (2 a_{0} + 3) x - a_{0}^{2} + 4 π

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + 3 a_{0} + 4 π)

Find the slope of

f (x) = x^{2} + 3 x + 4 π : \frac{df ( x )}{d x} = 2 x + 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2 a_{0} + 3

Find the line with slope m=

2 a_{0} + 3

and passing through

(a_{0}, a_{0}^{2} + 3 a_{0} + 4 π) : y = (2 a_{0} + 3) x - a_{0}^{2} + 4 π

y = (2 a_{0} + 3) x - a_{0}^{2} + 4 π

t \to 0 lim (2 e^{- t})

x \to 0 lim (\frac{8 x ^{2} - 2 x}{2 x})

\int (2 x - x)^{2} d x

\frac{\partial}{\partial x} (4 sin (x) cos (y))

\frac{\partial}{\partial K} (L^{\frac{1}{2}} K^{\frac{1}{2}})

What is the tangent of f(x)=x^2+3x+4pi ?
The tangent of f(x)=x^2+3x+4pi is y=(2a_{0}+3)x-a_{0}^2+4pi