What is the sum from n=0 to infinity of (2^2)/(3^2) ?

The sum from n=0 to infinity of (2^2)/(3^2) is diverges

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sum from n=0 to infinity of (2^2)/(3^2)

n = 0 \sum \infty \frac{2 ^{2}}{3 ^{2}}

diverges

Solution steps

n = 0 \sum \infty \frac{2 ^{2}}{3 ^{2}}

Every infinite sum of a non-zero constant diverges

= diverges

\frac{\partial}{\partial s} (- 3 s^{2} t^{2})

\frac{d y}{d x} = \frac{y ^{3}}{3 x + 1}, y (0) = - 1

\frac{2}{t ^{3}}

y^{^{'}} + 3 y = x e^{- 2 x}

\frac{\partial}{\partial y} (- sin (x) sin (y))

What is the sum from n=0 to infinity of (2^2)/(3^2) ?
The sum from n=0 to infinity of (2^2)/(3^2) is diverges