What is the integral from pi/2 to pi of-cos(x) ?

The integral from pi/2 to pi of-cos(x) is 1

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integral from pi/2 to pi of-cos(x)

\int_{\frac{π}{2}}^{π} - cos (x) d x

1

Solution steps

\int_{\frac{π}{2}}^{π} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{\frac{π}{2}}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{\frac{π}{2}}^{π}

Compute the boundaries:

- 1

= - (- 1)

Simplify

= 1

\int x^{2} e^{- x} d x

h (t) = 3 ln (t^{6})

\int 24 + cos (x) d x

\frac{- 4 x}{x ^{2} + 1} (- 1.2)

\frac{d}{d x} (x^{2} + x z - y + y^{2} + y z + 3 z^{2})

What is the integral from pi/2 to pi of-cos(x) ?
The integral from pi/2 to pi of-cos(x) is 1