What is the derivative of 6x^{-3} ?

The derivative of 6x^{-3} is -(18)/(x^4)

What is the first derivative of 6x^{-3} ?

The first derivative of 6x^{-3} is -(18)/(x^4)

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\frac{d}{d x} (6 x^{- 3})

- \frac{18}{x ^{4}}

Solution steps

\frac{d}{d x} (6 x^{- 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 (- 3 x^{- 3 - 1})

Simplify

6 (- 3 x^{- 3 - 1}) : - \frac{18}{x ^{4}}

= - \frac{18}{x ^{4}}

x \to \infty lim (y^{x})

\frac{2 t + 1}{t + 3}

\frac{\partial}{\partial x} (e^{x^{2} - y})

8 x + 9 x e^{x}

\int 2 ln (t) d t

What is the derivative of 6x^{-3} ?
The derivative of 6x^{-3} is -(18)/(x^4)
What is the first derivative of 6x^{-3} ?
The first derivative of 6x^{-3} is -(18)/(x^4)