What is the solution for y^{''}-3y^'+2y=0,y(0)=4,y^'(0)=7 ?

The solution for y^{''}-3y^'+2y=0,y(0)=4,y^'(0)=7 is y=3e^{2t}+e^t

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y^{''}-3y^'+2y=0,y(0)=4,y^'(0)=7

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 4, y^{^{'}} (0) = 7

y = 3 e^{2 t} + e^{t}

Solution steps

y^{''} (t) - 3 y^{'} (t) + 2 y = 0

Solve linear ODE:

y = 3 e^{2 t} + e^{t}

y = 3 e^{2 t} + e^{t}

\frac{\partial}{\partial z} (x^{2} + y^{2} + z^{2})

y^{^{'}} + 9 x e^{y} = 0

\int (x - 1)^{2} (e^{x + 1} - 1) d x

x^{2} - 7 x + 7

\frac{\partial}{\partial y} (\frac{3 x}{y})

What is the solution for y^{''}-3y^'+2y=0,y(0)=4,y^'(0)=7 ?
The solution for y^{''}-3y^'+2y=0,y(0)=4,y^'(0)=7 is y=3e^{2t}+e^t