What is the integral of 5xsqrt(x-1) ?

The integral of 5xsqrt(x-1) is 2(x-1)^{5/2}+10/3 (x-1)^{3/2}+C

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integral of 5xsqrt(x-1)

\int 5 x x - 1 d x

2 (x - 1)^{\frac{5}{2}} + \frac{10}{3} (x - 1)^{\frac{3}{2}} + C

Solution steps

\int 5 x x - 1 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 5 \cdot \int x x - 1 d x

Apply u-substitution

: \int (u + 1) u d u

= 5 \cdot \int (u + 1) u d u

Expand

(u + 1) u : u^{\frac{3}{2}} + u

= 5 \cdot \int u^{\frac{3}{2}} + u d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 5 (\int u^{\frac{3}{2}} d u + \int u d u)

\int u^{\frac{3}{2}} d u = \frac{2}{5} u^{\frac{5}{2}}

\int u d u = \frac{2}{3} u^{\frac{3}{2}}

= 5 (\frac{2}{5} u^{\frac{5}{2}} + \frac{2}{3} u^{\frac{3}{2}})

Substitute back

u = x - 1

= 5 (\frac{2}{5} (x - 1)^{\frac{5}{2}} + \frac{2}{3} (x - 1)^{\frac{3}{2}})

Simplify

5 (\frac{2}{5} (x - 1)^{\frac{5}{2}} + \frac{2}{3} (x - 1)^{\frac{3}{2}}) : 2 (x - 1)^{\frac{5}{2}} + \frac{10}{3} (x - 1)^{\frac{3}{2}}

= 2 (x - 1)^{\frac{5}{2}} + \frac{10}{3} (x - 1)^{\frac{3}{2}}

Add a constant to the solution

= 2 (x - 1)^{\frac{5}{2}} + \frac{10}{3} (x - 1)^{\frac{3}{2}} + C

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What is the integral of 5xsqrt(x-1) ?
The integral of 5xsqrt(x-1) is 2(x-1)^{5/2}+10/3 (x-1)^{3/2}+C