en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of 1+xe^x

Solution

\int_{1}^{2} 1 + x e^{x} d x

Solution

1 + e^{2}

+1

Solution steps

\int_{1}^{2} 1 + x e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d x + \int_{1}^{2} x e^{x} d x

\int_{1}^{2} 1 d x = 1

\int_{1}^{2} x e^{x} d x = e^{2}

= 1 + e^{2}

Popular Examples

integral from-1 to 1 of (2-2x^2)

\int_{- 1}^{1} (2 - 2 x^{2}) d x

integral from 1 to 2 of 2^x

\int_{1}^{2} 2^{x} d x

integral from 1 to 4 of 2x-x^2

\int_{1}^{4} 2 x - x^{2} d x

integral from 0 to 2 of t/(sqrt(5+t^2))

\int_{0}^{2} \frac{t}{5 + t ^{2}} d t

integral from 1 to e of ln(\sqrt[x]{x})

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of 1+xe^x ?
The integral from 1 to 2 of 1+xe^x is 1+e^2