What is the integral from 0 to pi of (4cos(x)+3) ?

The integral from 0 to pi of (4cos(x)+3) is 3pi

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integral from 0 to pi of (4cos(x)+3)

\int_{0}^{π} (4 cos (x) + 3) d x

3 π

Decimal

9.42477 \dots

Solution steps

\int_{0}^{π} 4 cos (x) + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 4 cos (x) d x + \int_{0}^{π} 3 d x

\int_{0}^{π} 4 cos (x) d x = 0

\int_{0}^{π} 3 d x = 3 π

= 0 + 3 π

Simplify

= 3 π

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What is the integral from 0 to pi of (4cos(x)+3) ?
The integral from 0 to pi of (4cos(x)+3) is 3pi