What is the integral from 1 to 2 of (1/(x^3)) ?

The integral from 1 to 2 of (1/(x^3)) is 3/8

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integral from 1 to 2 of (1/(x^3))

\int_{1}^{2} (\frac{1}{x ^{3}}) d x

\frac{3}{8}

Decimal

0.375

Solution steps

\int_{1}^{2} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{1}^{2}

= [- \frac{1}{2 x ^{2}}]_{1}^{2}

Compute the boundaries:

\frac{3}{8}

= \frac{3}{8}

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What is the integral from 1 to 2 of (1/(x^3)) ?
The integral from 1 to 2 of (1/(x^3)) is 3/8