What is the solution for x^'=(x-17)^2 ?

The solution for x^'=(x-17)^2 is x=-1/(t+c_{1)}+(17t)/(t+c_{1)}+(17c_{1})/(t+c_{1)}

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x^'=(x-17)^2

x^{^{'}} = (x - 17)^{2}

x = - \frac{1}{t + c _{1}} + \frac{17 t}{t + c _{1}} + \frac{17 c _{1}}{t + c _{1}}

Solution steps

x^{'} (t) = (x - 17)^{2}

Solve separable ODE:

x = - \frac{1}{t + c _{1}} + \frac{17 t}{t + c _{1}} + \frac{17 c _{1}}{t + c _{1}}

x = - \frac{1}{t + c _{1}} + \frac{17 t}{t + c _{1}} + \frac{17 c _{1}}{t + c _{1}}

f (x) = \frac{7}{x + 8}, (5, \frac{7}{13})

y^{^{'}} = 0.06 (y - 65)

n = 1 \sum \infty \frac{n}{2 n + 1}

\frac{d}{d x} (e^{x} + e^{- 3 x})

\frac{2 \cdot d y}{d x} + 100 \cdot y = 30 \cdot sin (60 x), y (0) = 0

What is the solution for x^'=(x-17)^2 ?
The solution for x^'=(x-17)^2 is x=-1/(t+c_{1)}+(17t)/(t+c_{1)}+(17c_{1})/(t+c_{1)}