What is the derivative of 75(1-8/x) ?

The derivative of 75(1-8/x) is (600)/(x^2)

What is the first derivative of 75(1-8/x) ?

The first derivative of 75(1-8/x) is (600)/(x^2)

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derivative of

75 (1 - \frac{8}{x})

\frac{600}{x ^{2}}

Solution steps

\frac{d}{d x} (75 (1 - \frac{8}{x}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 75 \frac{d}{d x} (1 - \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 75 (\frac{d}{d x} (1) - \frac{d}{d x} (\frac{8}{x}))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= 75 (0 - (- \frac{8}{x ^{2}}))

Simplify

75 (0 - (- \frac{8}{x ^{2}})) : \frac{600}{x ^{2}}

= \frac{600}{x ^{2}}

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What is the derivative of 75(1-8/x) ?
The derivative of 75(1-8/x) is (600)/(x^2)
What is the first derivative of 75(1-8/x) ?
The first derivative of 75(1-8/x) is (600)/(x^2)