What is the derivative of f(x)=4x^4-5x-3 ?

The derivative of f(x)=4x^4-5x-3 is 16x^3-5

What is the first derivative of f(x)=4x^4-5x-3 ?

The first derivative of f(x)=4x^4-5x-3 is 16x^3-5

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derivative of

f (x) = 4 x^{4} - 5 x - 3

16 x^{3} - 5

Solution steps

\frac{d}{d x} (4 x^{4} - 5 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{4}) - \frac{d}{d x} (5 x) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{4}) = 16 x^{3}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (3) = 0

= 16 x^{3} - 5 - 0

Simplify

= 16 x^{3} - 5

\int_{0}^{2} e^{- t^{2}} d t

\int \frac{2 x + 1}{x ^{2} + x + 1} d x

x = - y - 5, x = 5 y - 11, y = 0

\int (sec^{2} (x) + 4) d x

\int \frac{( 1 - x )}{x} d x

What is the derivative of f(x)=4x^4-5x-3 ?
The derivative of f(x)=4x^4-5x-3 is 16x^3-5
What is the first derivative of f(x)=4x^4-5x-3 ?
The first derivative of f(x)=4x^4-5x-3 is 16x^3-5