What is the integral of sin(t)*cos(t) ?

The integral of sin(t)*cos(t) is (sin^2(t))/2+C

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integral of sin(t)*cos(t)

\int sin (t) \cdot cos (t) d t

\frac{sin ^{2} ( t )}{2} + C

Solution steps

\int sin (t) cos (t) d t

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{u ^{2}}{2}

= \frac{u ^{2}}{2}

Substitute back

u = sin (t)

= \frac{sin ^{2} ( t )}{2}

Add a constant to the solution

= \frac{sin ^{2} ( t )}{2} + C

x \to 2 lim (3 x^{2} + 2 x)

x = y, x = 2 - y, y = 0

g (x) = x^{3} - 7 x^{2} + 2 x + 40

\frac{d}{d x} (2 e^{- 4 x})

\int \frac{1}{( 9 x ^{2} + 1 ) ^{\frac{5}{2}}} d x

What is the integral of sin(t)*cos(t) ?
The integral of sin(t)*cos(t) is (sin^2(t))/2+C