What is area x=sqrt(y),x=2-y,y=0 ?

The answer to area x=sqrt(y),x=2-y,y=0 is No Solution

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area x=sqrt(y),x=2-y,y=0

area

x = y, x = 2 - y, y = 0

No Solution

Solution steps

Isolate

y

for

x = y : y = x^{2} {x \geq 0}

Isolate

y

for

x = 2 - y : y = 2 - x

f_{1} (x) = x^{2}

f_{2} (x) = 2 - x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

x^{2} = 2 - x : x = 1, x = - 2

x^{2} = 0 : x = 0

2 - x = 0 : x = 2

Curves not bounded

= No Solution

g (x) = x^{3} - 7 x^{2} + 2 x + 40

\frac{d}{d x} (2 e^{- 4 x})

\int \frac{1}{( 9 x ^{2} + 1 ) ^{\frac{5}{2}}} d x

x = - 1, x = y^{3}, [0, 1]

\frac{d}{d x} (8 + cot^{2} (x))

What is area x=sqrt(y),x=2-y,y=0 ?
The answer to area x=sqrt(y),x=2-y,y=0 is No Solution