What is the derivative of ln(x^2)-3 ?

The derivative of ln(x^2)-3 is 2/x

What is the first derivative of ln(x^2)-3 ?

The first derivative of ln(x^2)-3 is 2/x

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derivative of

ln (x^{2}) - 3

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (x^{2}) - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x^{2})) - \frac{d}{d x} (3)

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

\frac{d}{d x} (3) = 0

= \frac{2}{x} - 0

Simplify

= \frac{2}{x}

\frac{e ^{x}}{2} + \frac{e ^{- x}}{2}

\frac{( x ^{3} - x ^{2} + 2 )}{( x ^{2} - 4 )}

2 x^{2} + 9

2 x^{2} + 2

sin^{- 2} (x)

What is the derivative of ln(x^2)-3 ?
The derivative of ln(x^2)-3 is 2/x
What is the first derivative of ln(x^2)-3 ?
The first derivative of ln(x^2)-3 is 2/x