What is the derivative of 2x^3+3 ?

The derivative of 2x^3+3 is 6x^2

What is the first derivative of 2x^3+3 ?

The first derivative of 2x^3+3 is 6x^2

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derivative of

2 x^{3} + 3

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3} + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3) = 0

= 6 x^{2} + 0

Simplify

= 6 x^{2}

\frac{1}{p}

\frac{1}{( 2 x - 1 )}

x^{2} y + 1

ln (x) ln (2 x)

\frac{d}{d x} (\frac{4}{2 x ^{2} - ( + 4 ) ( - 3 ) - ( - 6 ) ( - 2 )})