What is the d/(d{r)}({r}^3-{r}^2) ?

The d/(d{r)}({r}^3-{r}^2) is 3{r}^2-2{r}

What is the first d/(d{r)}({r}^3-{r}^2) ?

The first d/(d{r)}({r}^3-{r}^2) is 3{r}^2-2{r}

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\frac{d}{d r} (r^{3} - r^{2})

3 r^{2} - 2 r

Solution steps

\frac{d}{d r} (r^{3} - r^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (r^{3}) - \frac{d}{d r} (r^{2})

\frac{d}{d r} (r^{3}) = 3 r^{2}

\frac{d}{d r} (r^{2}) = 2 r

= 3 r^{2} - 2 r

\frac{d}{d x} (x_{6} x^{2} + 9)

x = 5 t^{2} - 2 t + 7

\frac{d}{d a} (1 - 8 sin^{2} (a) cos^{2} (a))

(\frac{1}{5})^{x}

\frac{( x + 1 ) ( x - 2 )}{x ^{2}}

What is the d/(d{r)}({r}^3-{r}^2) ?
The d/(d{r)}({r}^3-{r}^2) is 3{r}^2-2{r}
What is the first d/(d{r)}({r}^3-{r}^2) ?
The first d/(d{r)}({r}^3-{r}^2) is 3{r}^2-2{r}