What is the d/(d{r)}(5({r}-2*{p})) ?

The d/(d{r)}(5({r}-2*{p})) is 5

What is the first d/(d{r)}(5({r}-2*{p})) ?

The first d/(d{r)}(5({r}-2*{p})) is 5

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\frac{d}{d r} (5 (r - 2 \cdot p))

5

Solution steps

\frac{d}{d r} (5 (r - 2 p))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d r} (r - 2 p)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 5 (\frac{d}{d r} (r) - \frac{d}{d r} (2 p))

\frac{d}{d r} (r) = 1

\frac{d}{d r} (2 p) = 0

= 5 (1 - 0)

Simplify

= 5

\frac{d}{d t} (65 + 2 t - 3 t^{2})

- 2 ln (x)

f (x) = (x + sin (x))^{2}

\frac{d}{d x} (ln ((x - b)^{2}) - ln ((y - a)^{2}))

f (x) = x^{2} - 4 x + 9

What is the d/(d{r)}(5({r}-2*{p})) ?
The d/(d{r)}(5({r}-2*{p})) is 5
What is the first d/(d{r)}(5({r}-2*{p})) ?
The first d/(d{r)}(5({r}-2*{p})) is 5