What is the first derivative of 4x-5 ?

The first derivative of 4x-5 is 4

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derivative of 4x-5

derivative of

4 x - 5

4

Solution steps

\frac{d}{d x} (4 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 4 - 0

Simplify

= 4

(e^{x + 1})^{\frac{1}{2}}

\frac{d}{d t} (100 - 10 t + 6 t^{2})

y = x^{7} + 3 x^{5} + 1

4 x^{\frac{1}{3}}

2 sin^{2} (t) + 8 cos^{2} (t)