What is the tangent of f(x)=1-2x^2,-7,\at x=2 ?

The tangent of f(x)=1-2x^2,-7,\at x=2 is y=-8x+9

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tangent of f(x)=1-2x^2,-7,\at x=2

tangent of

f (x) = 1 - 2 x^{2}, - 7, at x = 2

y = - 8 x + 9

Solution steps

Find the tangent point:

(2, - 7)

Find the slope of

f (x) = 1 - 2 x^{2} : \frac{df ( x )}{d x} = - 4 x

Compute the slope of

f (x) = 1 - 2 x^{2}

x = 2 : m = - 8

Find the line with slope m=

- 8

and passing through

(2, - 7) : y = - 8 x + 9

y = - 8 x + 9

f (x) = 5 x - 4 x, at x = 1

y = \frac{1}{5 + 2 x}, (2, \frac{1}{9})

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4, y (0) = - 4

\int x^{3} x^{2} + 45 d x

What is the tangent of f(x)=1-2x^2,-7,\at x=2 ?
The tangent of f(x)=1-2x^2,-7,\at x=2 is y=-8x+9