What is the tangent of f(x)=5x-4sqrt(x),\at x=1 ?

The tangent of f(x)=5x-4sqrt(x),\at x=1 is y=3x-2

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tangent of f(x)=5x-4sqrt(x),\at x=1

tangent of

f (x) = 5 x - 4 x, at x = 1

y = 3 x - 2

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = 5 x - 4 x : \frac{df ( x )}{d x} = 5 - \frac{2}{x}

Compute the slope of

f (x) = 5 x - 4 x

x = 1 : m = 3

Find the line with slope m=

3

and passing through

(1, 1) : y = 3 x - 2

y = 3 x - 2

y = \frac{1}{5 + 2 x}, (2, \frac{1}{9})

\frac{y ^{^{'}} - e ^{- t} + 4}{y} = - 4, y (0) = - 4

\int x^{3} x^{2} + 45 d x

(2 y + 1) d x + (\frac{x ^{2} - y}{x}) d y = 0

\int_{0}^{2} (x (64 - (x + 3)^{3})) d x

What is the tangent of f(x)=5x-4sqrt(x),\at x=1 ?
The tangent of f(x)=5x-4sqrt(x),\at x=1 is y=3x-2