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Popular >

y^'+2y=-8

Solution

y^{^{'}} + 2 y = - 8

Solution

y = e^{- 2 t + c_{1}} - 4

Solution steps

y^{'} (t) + 2 y = - 8

Solve separable ODE:

y = e^{- 2 t + c_{1}} - 4

y = e^{- 2 t + c_{1}} - 4

Popular Examples

(dy)/(dx)=-3/5 x^7y^3

\frac{d y}{d x} = - \frac{3}{5} x^{7} y^{3}

(dx)/(dy)+2xy^2=0

\frac{d x}{d y} + 2 x y^{2} = 0

(x^2+1)(dy)/(dx)+3x(y-1)=0,y(0)=5

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0, y (0) = 5

(x^3+1)y^'=x^2y

(x^{3} + 1) y^{^{'}} = x^{2} y

y^2(x+1)+2xyy^'=0

y^{2} (x + 1) + 2 x y y^{^{'}} = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=-8 ?
The solution for y^'+2y=-8 is y=e^{-2t+c_{1}}-4