What is the integral of sqrt(x)+\sqrt[3]{x} ?

The integral of sqrt(x)+\sqrt[3]{x} is 2/3 x^{3/2}+3/4 x^{4/3}+C

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integral of sqrt(x)+\sqrt[3]{x}

\frac{2}{3} x^{\frac{3}{2}} + \frac{3}{4} x^{\frac{4}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

= \frac{2}{3} x^{\frac{3}{2}} + \frac{3}{4} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} + \frac{3}{4} x^{\frac{4}{3}} + C

\int \frac{2}{1 - x} d x

y^{^{'}} - y = x + 1

\frac{2 s}{s ^{2} - 8 s + 6}

\frac{d}{d x} (x^{\frac{l n ( 2 )}{( 1 + l n ( x ) )}})

f (x) = 12 (x - (\frac{1}{x}))^{4}, at x = 2

What is the integral of sqrt(x)+\sqrt[3]{x} ?
The integral of sqrt(x)+\sqrt[3]{x} is 2/3 x^{3/2}+3/4 x^{4/3}+C